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Titrate the base trimethylamine (TMA) with 0.126 M HCl. (CH)3N(aq) + H2O(l) (CH3)3NH+(aq) + OH-(aq)

Kb = 6.45 x 10-5

There are 0.00615 moles of TMA in 42.5 mL H2O before titration begins.

What percent of TMA is in the protonated form at the beginning of the titration?

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